The vapour pressure of benzene and its s...

The vapour pressure of benzene and its solution with a non-electrolyte are 640 and 600 mm respectively. The molality of the solution is -

0.8

0.86

0.09

0.95

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Vapour pressure of a solvent is the pressure exterted by vapour when they are in equilibrium with its solvent at that temperature. The vapour pressure of solvent is dependent of nature of solvent, temperature, addition of non-volatile solute as well as nature of solute to dissociate or associate. The vapour pressure of a mixture obtained by mixing two valatile liquids is given by P_(M) = P_(A)^(@).X_(A)+P_(B)^(@).X_(B) where P_(A)^(@) and P_(B)^(@) are vapour pressures of pure components A and B and X_(A), X_(B) are their mole fractions in mixture. For solute-solvent system, the relatio becomes P_(M) = P_(A)^(@).X_(A) where B is non-volatile solute. The vapour pressure of benzene and its solution with a non-electrolyte are 640 and 600 mm respectively. The molality of solution is:

Equal moles of benzene and toluene are mixed. The vapour pressure of benzene and toluene in pure state are 700 and 600 mm Hg respectively. The mole fraction of benzene in vapour state is :-

The vapour pressure of pure benzene and toluene are 160 and 60 mm Hg respectively. The mole fraction of benzene in vapour phase in contact with equimolar solution of benzene and toluene is :

The relative lowering of vapour pressure of an aqueous solution containing a non-volatile solute, is 0.0125. The molality of the solution is

The vapour pressure of 2.1% solution of a non- electrolyte in water at 100^(@) C is 755 mm Hg. Calculate the molar mass of the solute .

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