The product A, B, C and D in the reaction `A +B overset("Heat")larr H-COOH underset(H_(2)SO_(4)) overset("Heat")to C+D` are given by the set -

Options

A. `CO, H_(2)O, CO_(2), H_(2)`
B. `CO_(2), H_(2)O, CO, H_(2)`
C. `CO_(2), H_(2), CO, H_(2)O`
D. `CO, H_(2), CO_(2), H_(2)O`

Answer

To solve the problem, we need to identify the reactants (A and B) and the products (C and D) in the given reaction involving formic acid (H-COOH) and sulfuric acid (H₂SO₄) under heat.

### Step-by-Step Solution:

1. **Identify the Reaction**:
The reaction is given as:
\[ A + B \overset{\text{Heat}}{\longrightarrow} \text{H-COOH} \underset{\text{H}_2\text{SO}_4}{\overset{\text{Heat}}{\longrightarrow}} C + D \]
Here, we need to find what A, B, C, and D are.

2. **Determine Reactants A and B**:
- The reactants A and B are likely carbon monoxide (CO) and water (H₂O).
- When CO and H₂O react under heat, they produce hydrogen (H₂) and carbon dioxide (CO₂) through the water gas shift reaction:
\[ \text{CO} + \text{H}_2\text{O} \overset{\text{Heat}}{\longrightarrow} \text{CO}_2 + \text{H}_2 \]
Therefore, we can assign:
- \( A = \text{CO} \)
- \( B = \text{H}_2\text{O} \)

3. **Identify Products C and D**:
- The product of heating formic acid (H-COOH) in the presence of sulfuric acid (H₂SO₄) leads to the decomposition of formic acid into carbon monoxide (CO) and water (H₂O):
\[ \text{H-COOH} \overset{\text{H}_2\text{SO}_4}{\text{Heat}}{\longrightarrow} \text{CO} + \text{H}_2\text{O} \]
Thus, we can assign:
- \( C = \text{CO} \)
- \( D = \text{H}_2\text{O} \)

4. **Final Assignment**:
- From the above deductions, we have:
- \( A = \text{CO} \)
- \( B = \text{H}_2\text{O} \)
- \( C = \text{CO} \)
- \( D = \text{H}_2\text{O} \)

### Summary of Assignments:
- \( A = \text{CO} \)
- \( B = \text{H}_2\text{O} \)
- \( C = \text{CO} \)
- \( D = \text{H}_2\text{O} \)