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In the reaction sequence CH(3)-CH(2)-COO...

In the reaction sequence `CH_(3)-CH_(2)-COOH`
`overset(Br_(2)//PBr_(3))tox overset(Br_(2))toy overset(H_(2)O)to`

A

x is `CH_(3)-CH_(2)-overset(O)overset(||)C-Br`

B

y is `CH_(3)-underset(Br)underset(|)(CH)-overset(O)overset(||)C-Br`

C

z is `CH_(3)- underset(Br)underset(|)(CH)-overset(O)overset(||)C-OH`

D

All are correct

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the reaction sequence step by step. The starting compound is propanoic acid (CH3CH2COOH), and we will go through the reactions involving bromine (Br2) and phosphorus tribromide (PBr3). ### Step 1: Reaction with Br2 and PBr3 1. **Starting Compound**: Propanoic acid (CH3CH2COOH). 2. **Reaction with PBr3**: The hydroxyl group (-OH) of the carboxylic acid is converted to a bromine atom (Br) due to the action of phosphorus tribromide (PBr3). This is a common reaction for converting alcohols and carboxylic acids to their corresponding bromides. 3. **Product**: The product after this step is 1-bromopropanoic acid (CH3CH2C(Br)=O). ### Step 2: Reaction with Br2 1. **Next Step**: The product from Step 1 (1-bromopropanoic acid) is then treated with Br2. 2. **Bromination**: The bromine will add to the carbon adjacent to the carbonyl group (the carbon with the bromine attached). This is known as the HVZ (Hunsdiecker-Van Duyne) reaction, where bromine replaces the hydrogen atom on the carbon adjacent to the carbonyl. 3. **Product**: The product after this step is 2-bromopropanoic acid (CH3C(Br)HCOOH). ### Step 3: Hydrolysis 1. **Final Step**: The product from Step 2 (2-bromopropanoic acid) is then hydrolyzed in the presence of water (H2O). 2. **Hydrolysis Reaction**: The bromine atom is replaced by a hydroxyl group (-OH) during hydrolysis. 3. **Final Product**: The final product after hydrolysis is propanoic acid (CH3CH(OH)COOH). ### Summary of Products - **X**: 1-bromopropanoic acid (CH3CH2C(Br)=O) - **Y**: 2-bromopropanoic acid (CH3C(Br)HCOOH) - **Z**: Propanoic acid (CH3CH(OH)COOH) ### Final Answer The final product after the entire reaction sequence is propanoic acid (CH3CH(OH)COOH). ---
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