In the given reaction sequene :
`C_(6)H_(5)-CN overset((H_(2)O)//overset(o+)(H)//Delta)toA overset(SOCl_(2))toB overset(C_(6)H_(6)//AlCl_(3))toC`, (C) is

Options

A. `C_(6)H_(5)-overset(O)overset(||)C-C_(6)H_(5)`
B. `C_(6)H_(5)-overset(O)overset(||)C-O-C_(6)H_(5)`
C. `C_(6)H_(5)-overset(O)overset(||)C-NH-C_(6)H_(5)`
D. `C_(6)H_(5)-overset(O)overset(||)C-O-C_(6)H_(5)`

Answer

To solve the given reaction sequence, we need to identify the compounds A, B, and C step by step. Let's break down the reaction sequence provided:

1. **Starting Compound**: The starting compound is **C6H5CN** (benzonitrile).

2. **Step 1 - Hydrolysis of Benzonitrile**:
- When benzonitrile (C6H5CN) is treated with water (H2O) and heat, it undergoes hydrolysis.
- The nitrile group (CN) is converted into a carboxylic acid (COOH).
- The product formed is **benzoic acid (C6H5COOH)**.
- Therefore, **A = C6H5COOH**.

3. **Step 2 - Reaction with Thionyl Chloride (SOCl2)**:
- Benzoic acid (A) reacts with thionyl chloride (SOCl2) to convert the carboxylic acid group into an acyl chloride.
- The reaction replaces the hydroxyl group (OH) of the carboxylic acid with a chlorine atom (Cl).
- The product formed is **benzoyl chloride (C6H5COCl)**.
- Therefore, **B = C6H5COCl**.

4. **Step 3 - Friedel-Crafts Acylation**:
- Benzoyl chloride (B) is then reacted with benzene (C6H6) in the presence of aluminum chloride (AlCl3), which acts as a Lewis acid.
- This reaction is known as Friedel-Crafts acylation, where the acyl group from benzoyl chloride is introduced into the benzene ring.
- The product formed is **acetophenone (C6H5COC6H5)**.
- Therefore, **C = C6H5COC6H5**.

### Final Answer:
C = Acetophenone (C6H5COC6H5)