`(CH_(3))_(3)C-overset(O)overset(||)C-Cl+LiAlH_(4)" (excess)" to overset(H_(3)O^(o+))to X,X` is

Options

A. `(CH_(3))_(3)C-overset(O)overset(||)C-H`
B. `CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-CH_(2)-OH`
C. `CH_(3)-underset(CH_(3))underset(|)(CH)-CH_(2)-CH_(2)-OH`
D. `CH_(3)-CH_(2)-CH_(2)-CH_(2)-CH_(2)-OH`

Answer

To solve the problem, we need to analyze the reaction of the compound `(CH₃)₃C-C(=O)Cl` (which is a carbonyl compound with a chlorine atom) with Lithium Aluminum Hydride (LiAlH₄) in excess, followed by treatment with H₃O⁺ (acidic workup).

### Step-by-Step Solution:

1. **Identify the Reactant:**
The reactant is `(CH₃)₃C-C(=O)Cl`, which can be broken down as follows:
- It has a carbon chain with three methyl groups (tert-butyl group) attached to a carbon that is double-bonded to oxygen (carbonyl) and has a chlorine atom.

2. **First Reaction with LiAlH₄:**
Lithium Aluminum Hydride (LiAlH₄) is a strong reducing agent. When it reacts with the carbonyl compound, it will provide a hydride ion (H⁻) that will attack the carbon atom of the carbonyl group.
- The hydride ion attacks the carbonyl carbon, leading to the formation of a tetrahedral intermediate. The oxygen atom will gain a negative charge.

3. **Formation of Aldehyde:**
After the hydride attack, the tetrahedral intermediate will collapse, resulting in the elimination of the chlorine atom (Cl⁻) as a leaving group. This will convert the carbonyl compound into an aldehyde:
- The product at this stage is `(CH₃)₃C-CHO` (tert-butyl aldehyde).

4. **Second Reaction with Excess LiAlH₄:**
Since LiAlH₄ is in excess, it will react again with the aldehyde. The hydride ion will again attack the carbonyl carbon of the aldehyde.
- This leads to the formation of another tetrahedral intermediate, where the oxygen now has a negative charge.

5. **Formation of Alcohol:**
The tetrahedral intermediate will again collapse, and the oxygen will be protonated by the subsequent treatment with H₃O⁺ (acidic workup). This will lead to the formation of an alcohol:
- The final product is `(CH₃)₃C-CH₂OH` (tert-butyl alcohol).

### Final Answer:
The final product (X) after the reaction is `(CH₃)₃C-CH₂OH`.