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Which of the following has been arranged...

Which of the following has been arranged in increasing order of size of the hybrid orbitals ?

A

`sp lt sp^2 lt sp^3`

B

`sp^3 lt sp^2 lt sp`

C

`sp^2 lt sp^3 lt sp`

D

`sp^2 lt sp lt sp^3`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the increasing order of size of hybrid orbitals, we will analyze the hybridization types (sp, sp², sp³) and their corresponding s-character percentages. ### Step-by-Step Solution: 1. **Understand Hybridization Types**: - Hybridization involves the mixing of atomic orbitals to form new hybrid orbitals. The common types are sp, sp², and sp³. 2. **Calculate the Percentage of s-Character**: - For **sp hybridization**: - There is 1 s orbital and 1 p orbital. - Total orbitals = 1 (s) + 1 (p) = 2. - Percentage of s-character = (1/2) × 100 = 50%. - For **sp² hybridization**: - There is 1 s orbital and 2 p orbitals. - Total orbitals = 1 (s) + 2 (p) = 3. - Percentage of s-character = (1/3) × 100 = 33.33%. - For **sp³ hybridization**: - There is 1 s orbital and 3 p orbitals. - Total orbitals = 1 (s) + 3 (p) = 4. - Percentage of s-character = (1/4) × 100 = 25%. 3. **Relate s-Character to Orbital Size**: - The size of hybrid orbitals is inversely proportional to the percentage of s-character. This means: - More s-character → smaller orbital size. - Less s-character → larger orbital size. 4. **Determine the Order of Sizes**: - From the percentages calculated: - sp has the highest s-character (50%), hence the smallest size. - sp² has a lower s-character (33.33%), hence a larger size than sp. - sp³ has the least s-character (25%), hence the largest size. - Therefore, the order of sizes from smallest to largest is: - sp < sp² < sp³. 5. **Final Increasing Order of Size**: - The increasing order of size of the hybrid orbitals is: - sp < sp² < sp³. ### Final Answer: The correct increasing order of size of the hybrid orbitals is: **sp < sp² < sp³**.
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