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Which of the following has fractional bo...

Which of the following has fractional bond order ?

A

`O_2^(2+)`

B

`O_2^(2-)`

C

`F_2^(2-)`

D

`H_2^(-)`

Text Solution

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The correct Answer is:
To determine which of the given molecules has a fractional bond order, we will follow these steps: ### Step 1: Understand Bond Order The bond order can be calculated using the formula: \[ \text{Bond Order} = \frac{(\text{Number of bonding electrons}) - (\text{Number of antibonding electrons})}{2} \] A fractional bond order indicates that the molecule does not have a whole number of bonds. ### Step 2: Analyze Each Option We will analyze the bond order for each molecule mentioned in the video transcript. #### Option 1: O2 - **Electrons**: O2 has 16 electrons. - **Molecular Orbital Filling**: - σ1s (2), σ1s* (2), σ2s (2), σ2s* (2), σ2p (2), π2p (4), π*2p (2). - **Bonding Electrons**: 10 (σ1s, σ2s, σ2p, π2p) - **Antibonding Electrons**: 6 (σ1s*, σ2s*, π*2p) - **Bond Order Calculation**: \[ \text{Bond Order} = \frac{10 - 6}{2} = \frac{4}{2} = 2 \] - **Conclusion**: O2 has a bond order of 2 (not fractional). #### Option 2: O2^+ - **Electrons**: O2^+ has 15 electrons. - **Molecular Orbital Filling**: - σ1s (2), σ1s* (2), σ2s (2), σ2s* (2), σ2p (2), π2p (4), π*2p (1). - **Bonding Electrons**: 10 - **Antibonding Electrons**: 5 - **Bond Order Calculation**: \[ \text{Bond Order} = \frac{10 - 5}{2} = \frac{5}{2} = 2.5 \] - **Conclusion**: O2^+ has a bond order of 2.5 (not an integer, but still not fractional). #### Option 3: O2^2- - **Electrons**: O2^2- has 16 electrons. - **Molecular Orbital Filling**: - σ1s (2), σ1s* (2), σ2s (2), σ2s* (2), σ2p (2), π2p (4), π*2p (4). - **Bonding Electrons**: 10 - **Antibonding Electrons**: 4 - **Bond Order Calculation**: \[ \text{Bond Order} = \frac{10 - 4}{2} = \frac{6}{2} = 3 \] - **Conclusion**: O2^2- has a bond order of 3 (not fractional). #### Option 4: H2^- - **Electrons**: H2^- has 3 electrons. - **Molecular Orbital Filling**: - σ1s (2), σ1s* (1). - **Bonding Electrons**: 2 - **Antibonding Electrons**: 1 - **Bond Order Calculation**: \[ \text{Bond Order} = \frac{2 - 1}{2} = \frac{1}{2} = 0.5 \] - **Conclusion**: H2^- has a bond order of 0.5 (this is fractional). ### Final Answer The molecule that has a fractional bond order is **H2^-**. ---
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MOTION-CHEMICAL BONDING -EXERCISE -4 LEVEL-II
  1. Which of the following has fractional bond order ?

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  2. Which species has the maximum number of lone pair of electrons on the ...

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  3. The percentage of p-character in the orbitals forming p-p bonds in P4 ...

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  4. Among the following , the paramagnetic compound is :

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  5. The species having bond order different from that in CO is

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  6. The structure of XeO3 is :

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  7. Statement-I: p-Hydroxybenzoic acid has a lower boiling point that o-hy...

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  8. Statement I In water, orthoboric acid behaves as a weak monobasic acid...

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  9. Assertion (A) : Pb^(+4) compounds are stronger oxidiising agents than...

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  10. Match each of the diatomic molecules in Column I with its property/pro...

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  11. The nitrogen oxide (s) that contain (s) N-N bonds (s) is (are).

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  12. In the following reactions 2X+B(2)H(6) to [BH(2)(X)(2)]^(+){BH(4)]^(...

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  13. The number of water molecule(s) directly bonded to the metal centre in...

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  14. Based on VSEPR theory, the number of 90 degree F-Br-F angles in BrF(5)...

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  15. The value of n in the molecular fromula Ben Al2Si6 O(18).

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  16. What is the total number of diprotic acid among the following ? H3P...

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  17. Among the following, the number of elements showing only one non-zero ...

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  18. The species having pyramidal shape is

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  19. Assuming that Hund's rule is violated the bond order and magnetic natu...

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  20. All the compounds listed in Column I react with water. Match the resul...

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  21. The difference in the oxidation numbers of the two types of sulphur at...

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