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Which of the following is correct ?...

Which of the following is correct ?

A

During `N_2^+` formation, one electron is removed from the bonding molecular orbitals

B

During `O_2^+` formation, one electron is removed from the antibonding molecular orbitals

C

During `O_2^-` formation, one electron is added to the bonding molecular orbitals

D

During `CN^–` formation, one electron is added to the bonding molecular orbitals

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The correct Answer is:
To solve the question regarding which statements about molecular orbitals are correct, we will analyze the formation of the molecular species mentioned in the video transcript step by step. ### Step-by-Step Solution: 1. **Understanding Molecular Orbital Theory (MOT)**: - Molecular Orbital Theory helps us understand the arrangement of electrons in molecules. Electrons occupy molecular orbitals that can be bonding or anti-bonding. 2. **Electron Count in N2**: - Nitrogen (N) has an atomic number of 7, so N2 has a total of 14 electrons (7 from each N atom). - The filling of molecular orbitals for N2 is as follows: - σ1s (2), σ1s* (2), σ2s (2), σ2s* (2), π2px (2), π2py (2), σ2pz (2). - Total: 2 + 2 + 2 + 2 + 2 + 2 = 14 electrons. 3. **Formation of N2+**: - When forming N2+, one electron is removed. According to MOT, this electron is removed from the σ2pz bonding molecular orbital. - Thus, N2+ has 13 electrons, and the filling is: - σ1s (2), σ1s* (2), σ2s (2), σ2s* (2), π2px (2), π2py (2), σ2pz (1). - Conclusion: It is correct that during N2 formation, one electron is removed from the bonding molecular orbital. 4. **Formation of O2**: - Oxygen (O) has an atomic number of 8, so O2 has 16 electrons. - The filling of molecular orbitals for O2 is: - σ1s (2), σ1s* (2), σ2s (2), σ2s* (2), π2px (2), π2py (2), σ2pz (2). - When forming O2+, one electron is removed from the π*2py or π*2px anti-bonding molecular orbitals. - Conclusion: It is correct that during O2 formation, one electron is removed from the anti-bonding molecular orbital. 5. **Formation of O2-**: - When O2 gains an electron to form O2-, it will fill the π*2py or π*2px anti-bonding orbital. - Thus, one electron is added to the anti-bonding molecular orbital. - Conclusion: This statement is correct. 6. **Formation of CN-**: - CN has a total of 14 electrons (C has 6 and N has 7). - The filling of molecular orbitals for CN- (adding one electron) will lead to the addition of an electron to the bonding molecular orbital. - Conclusion: It is correct that during CN- formation, one electron is added to the bonding molecular orbital. ### Final Conclusion: - All statements A, B, and D are correct based on the analysis of molecular orbital filling and electron transitions.
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MOTION-CHEMICAL BONDING -EXERCISE -2 LEVEL II
  1. Which of the following statement is/are correct

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  2. Given the species : N2, CO, CN^– and NO^+. Which of the following stat...

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  3. Which of the following is correct ?

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  4. Which possess fractional bond order ?

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  5. Which of the following have identical bond order?

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  6. Which of the following has unpaired electron(s)?

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  7. Which of the following pairs of species have the same bond order ?

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  8. Which of the following are diamagnetic ?

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  9. Which of the following are paramagnetic?

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  10. Which of the following species has a bond order other than 3?

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  11. Among the following, the species with one unpaired electron are:

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  12. Which of the following pairs have identical value of bond order?

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  13. Which of the following specie(s)/are linear?

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  14. On heating to 400-500^@C, relatively unstable hydrides and carbonates ...

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  15. Which of the following compound is/are predominantly ionic?

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  16. Which of the following statements is/are true?

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  17. Which of the following statements is/are true for BaO and MgO ?

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  18. Polarization is the distortion of the anion by an adjacenty placed cat...

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  19. Which of the following statement is/are correct regarding the compound...

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  20. Why do ionic compounds have high melting points?

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