Write the electronic structures of : (a) CO , (b) NO, (c) HF ,(d) HCl, based upon Molecular orbital (MO) diagram

Explanation

To find the electronic structures of CO, NO, HF, and HCl based on molecular orbital (MO) theory, we will follow these steps:

### Step 1: Determine the total number of valence electrons for each molecule.
- **CO (Carbon Monoxide)**: Carbon has 4 valence electrons, and Oxygen has 6. Total = 4 + 6 = 10 electrons.
- **NO (Nitric Oxide)**: Nitrogen has 5 valence electrons, and Oxygen has 6. Total = 5 + 6 = 11 electrons.
- **HF (Hydrogen Fluoride)**: Hydrogen has 1 valence electron, and Fluorine has 7. Total = 1 + 7 = 8 electrons.
- **HCl (Hydrogen Chloride)**: Hydrogen has 1 valence electron, and Chlorine has 7. Total = 1 + 7 = 8 electrons.

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