The hybridisation of atomic orbitals of nitrogen in `NO_2^+ , NO_3^- ` and `NH_4^(+)` are :

Options

A. `sp , sp^2, sp^3`
B. `sp^2 , sp, sp^3`
C. `sp, sp^3 , sp^2`
D. `sp^2,sp^3, sp`

Answer

B

Explanation

Count `sigma`-bond, lone pairs and unpaired electrons or count number of atoms directly attached, lone pairs and unpaired electrons.
When this is 2, then hybridisation = sp When this is 3, then hybridisation = `sp^2`
When this is 4, then hybidisation = `sp^3`