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The difference in the oxidation numbers of the two types of sulphur atoms in `Na_(2)S_(4)O_(6)` is:

Oxidation number of sulphur atom involved in coordinate bond formation is (+5) and that of middle sulphur atom is zero. Hence the difference in oxidation number of two types of sulphur aton will be (+5).]

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The correct Answer is:
5 OR 0
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