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Among the following, the correct stateme...

Among the following, the correct statement(s) is(are) :

A

`Al(CH_3)_3` has the three-centre two- electron bonds in its dimeric structure

B

`BH_3` has the three-centre two-electron bonds in its dimeric structure

C

The Lewis acidity of `BCl_3` is greater than that of `AlCl_3`

D

`AlCl_3` has the three-centre two-electron bonds in its dimeric structure

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AI Generated Solution

The correct Answer is:
To determine which statements are correct among the given options regarding chemical bonding, we will analyze each statement step by step. ### Step 1: Analyze the first statement about Al(CH3)3 - **Statement**: Al(CH3)3 has three-centered two-electron bonds in its dimeric structure. - **Analysis**: In the dimeric structure of Al(CH3)3, we can visualize that each aluminum atom is bonded to three methyl groups (CH3). When two Al(CH3)3 units dimerize, they form a structure where the bonding involves three centers (two Al atoms and one C atom from the methyl groups) sharing two electrons. This confirms that the statement is **true**. ### Step 2: Analyze the second statement about B2H6 - **Statement**: B2H6 has three-centered two-electron bonds. - **Analysis**: In diborane (B2H6), the bonding involves the concept of "banana bonds," where two boron atoms share hydrogen atoms. Each bond can be viewed as a three-centered bond involving two boron atoms and one hydrogen atom, sharing two electrons. Thus, this statement is also **true**. ### Step 3: Analyze the third statement about Lewis acidity - **Statement**: The Lewis acidity of BCl3 is greater than that of AlCl3. - **Analysis**: BCl3 is a stronger Lewis acid compared to AlCl3 because boron has an empty p-orbital and can accept electron pairs more readily. In contrast, AlCl3 has a filled p-orbital due to back-bonding from chlorine, which reduces its Lewis acidity. Therefore, this statement is **true**. ### Step 4: Analyze the fourth statement about AlCl4 - **Statement**: AlCl4 is a three-centered two-electron species. - **Analysis**: AlCl4 involves aluminum bonded to four chlorine atoms. Each chlorine atom has a lone pair and can form dative bonds with aluminum. This results in a structure where there are four electrons involved in bonding, not two. Thus, this statement is **false**. ### Conclusion Based on the analysis: - The first, second, and third statements are **true**. - The fourth statement is **false**. ### Final Answer The correct statements are: 1. Al(CH3)3 has three-centered two-electron bonds in its dimeric structure. (True) 2. B2H6 has three-centered two-electron bonds. (True) 3. The Lewis acidity of BCl3 is greater than that of AlCl3. (True) 4. AlCl4 is a three-centered two-electron species. (False)
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