Certain quantity of current is passed through 2 voltameters connected in series and containing `XSO_4` (aq) and `Y_2SO_4` (aq) respectively. If the atomic masses of X and Y are in the ratio of 2 : 1 the ratio of the masses of Y liberated to that of X is

Options

A. `1:1`
B. `1:2`
C. `2:1`
D. `3:2`

Explanation

(A) `X^(2+)+2e^(-)toX,Y^(+)e^(-)toY`
2 `mol e^(-)` produce X=1 mol=1`xx` Mg
2 mol `e^(-)` produce Y=2`xxM//2=Mg`
Hence, ratio of the masses of Y:X is M:M or 1:1