The specific conductance of a 0.20 mol `L^(-1)` solution of an elctrolyte at `20^(@)C` is `2.48xx10^(-4)ohm^(-1)cm^(-1)`. The molar conductivity of the solution is -

Options

A. `1.24ohm^(-1)cm^2mol^(-1)`
B. `4.96ohm^(-1)cm^2mol^(-1)`
C. `1.24ohm^(-1)cm^(2)`
D. `4.96ohm^(-1)cm^(2)`

Explanation

To find the molar conductivity (\( \Lambda_m \)) of the given electrolyte solution, we can use the relationship between specific conductance (\( \kappa \)) and molar conductivity. Here are the steps to solve the problem:

### Step-by-Step Solution:

1. **Identify the Given Values**:
- Specific conductance (\( \kappa \)) = \( 2.48 \times 10^{-4} \, \Omega^{-1} \, \text{cm}^{-1} \)
- Concentration (\( C \)) = \( 0.20 \, \text{mol} \, \text{L}^{-1} \)

...