How many hour are required for a current of `3.0` ampere to decompose `18 g` water?

Explanation

`H_2O to H_2+1/2O_2[overset(2H^(+)+2etoH_2)(O^(2-)to1/2O_2+2e)]`
`:.` Eq of `H_2O=(i.t)/(96500)`
Equivalent weight of `H_2O`=18/2 as two electrons are used for 1mole `H_2O` to decomposer in `H_2` and `O_2`
`:.(18)/(18//2)=(3xxt)/(96500)`
`:.t=64333.3sec=1072.2` minute=17.87 hr