An electrochemical cell has two half cell reaction as, `A^(2+)+2e^-,E^0=0.34V`
`XtoX^(2+)+2e^-,E^0=+2.37V`. The cell voltage will be

Options

A. 2.71V
B. 2.03 V
C. -2.71V
D. -2.03V

Explanation

To calculate the cell voltage for the given electrochemical cell, we need to follow these steps:

### Step 1: Identify the Half-Reactions
We have two half-reactions:
1. \( A^{2+} + 2e^- \rightarrow A \) with \( E^0 = 0.34 \, \text{V} \)
2. \( X \rightarrow X^{2+} + 2e^- \) with \( E^0 = +2.37 \, \text{V} \)

### Step 2: Determine the Oxidation and Reduction Reactions
...