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E^(c-) of some elements are given as : ...

`E^(c-)` of some elements are given as `:`
`{:(I_(2)+2e^(-)rarr 2I^(c-),,,,E^(c-)=0.54V),(MnO_(4)^(c-)+8H^(o+)+5e^(-)rarr Mn^(2+)+4H_(2)O,,,,E^(c-)=1.52V),(Fe^(3+)+e^(-)rarr Fe^(2+),,,,E^(c-)=0.77V),(Sn^(4+)+2e^(-)rarr Sn^(2+),,,,E^(c-)=0.1V):}`
`a.` Select the stronges reductant and weakes oxidant among these elements.
`b.` Select the weakest reductant and strongest oxidant among these elements.

Text Solution

Verified by Experts

More or +ve is `E_(RP)^0`, more is the tendency for reduction or stronger is oxidant. Therefore, since maximum `E_(RP)^0` stands for :
`MnO_4^- +8H^+ +5e to Mn^(2+)+4H_2O,E_(RP)^0=+1.52V`
`:.` strongest oxidant : `MnO_4^-`, and conjugate reductant and vice-versa
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MnO_(4)^(-) + 8H^(+) + 5e^(-) rightarrow Mn^(2+) + 4H_(2)O , E^(@) = 1.51V MnO_(2) + 4H^(+) + 2e^(-) righarrow Mn^(2+) + 2H_(2)O E^(@) = 1.23V E_(MnO_(4)^(-)|MnO_(2)

The values of E^(@) of some of the reactions are given below : {:(I_(2)+2e^(-) rarr 2I^(-),,E^(@)=+0.54" volt"),(Cl_(2)+2e^(-) rarr 2Cl^(-),,E^(@)=+1.36" volt"),(Fe^(3+)+e^(-) rarr Fe^(2+),,E^(@)=+0.76" volt"),(Ce^(4+)+e^(-) rarr Ce^(3+),,E^(@)=+1.60" volt"),(Sn^(4+)+2e^(-) rarr Sn^(2+),,E^(2)=+0.15" volt"):} On the basis of the above data, answer the following questions : (a) Whether Fe^(3+) oxidises Ce^(3+) or not ? (b) Whether I_(2) displaces chlorine from KCl ? (c) Whether the reaction between FeCl_(3) and SnCl_(2) occurs or not ?

Given that I_(2)+2e^(-) rarr 2I^(c-)," "E^(c-)=0.54V Br_(2)+2e^(-) rarr 2Br^(-)," "E^(c-)=1.69V Predict which of the following is true.

Standard reduction potentials of the half reactions are given below {:(F_(2(g))+2e^(-) rarr 2F^(-)""_((aq)),,E^(@)=+2.85V), (Cl_(2(g))+2e^(-) rarr 2Cl^(-)""_((aq)),, E^(@)=+1.36V), (Br_(2(l))+2e^(-) rarr 2Br^(-)""_((aq)),,E^(@)=+1.06V), (l_(2(s))+2e^(-) rarr 2l^(-)""_((aq)),, E^(@)=+0.53V):} The strongest oxidising and reducing agents respectively are

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