A cell is constituted as follows
`Pt,H_(2(1atm))|HA_1|HA_2|H_(2(1 atm)),Pt`
The pH of two acids solutions HA, and `HA)2` are 5 and 3 respectively. The emf of the cell is

Options

A. 0.059V
B. 0.0295V
C. 0.118V
D. -0.118V

Explanation

To find the EMF of the cell constituted as follows: `Pt,H2(1atm)|HA1|HA2|H2(1atm),Pt`, where the pH of the two acid solutions HA1 and HA2 are 5 and 3 respectively, we can follow these steps:

### Step 1: Determine the Concentration of H⁺ Ions

The pH of a solution is related to the concentration of hydrogen ions (H⁺) by the formula:
\[ \text{pH} = -\log[H^+] \]

For HA1 (pH = 5):
...