A current of 1.70 ampere is passed through 300mL of 0.160M solution of `ZnSO_(4)` for 230 sec with a current efficiency of 90%. Find the molarity of `Zn^(2+)` after the deposition of Zn. Assume the volume of the solution deposition remains constant during elecyrolysis

Explanation

We know, `i=(70xx90)/(100)` ampere
`:.` Eq. of `Zn^(2+)` lost `=("it")/(96500)=(1.70xx90xx230)/(100xx96500)=3.646xx10^(-3)`
`:.` Meq. Of `Zn^(2+)` lost=3.646
Initial Meq. Of `Zn^(2+)=300xx0.160xx2`
`[Mxx2=N " for "Zn^(2+), Meq.=NxxV_(("in mL"))]=48xx2=96`j
`:.[ZnSO_4]=(92.354)/(2xx300)=0.154M`