If 0.01 M solution of an electrolyte has a resistance of 40 ohms in a cell having a cell constant of 0.4 `cm^(–1)` then its molar conductance in `ohm^(–1) cm^2 mol^(– 1)` will be

Options

A. `10^4`
B. `10^3`
C. `10^2`
D. 10

Explanation

To solve the problem of finding the molar conductance of a 0.01 M solution of an electrolyte with a resistance of 40 ohms and a cell constant of 0.4 cm⁻¹, we can follow these steps:

### Step 1: Write down the given values
- Concentration of the electrolyte (C) = 0.01 M
- Resistance (R) = 40 ohms
- Cell constant (k) = 0.4 cm⁻¹

### Step 2: Use the formula for conductivity (κ)
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