How much will the reduction potential of a hydrogen electrode change when its solution initially at `pH=0` is neutralized to `pH=7` ?

Options

A. Increase by 0.059 V
B. Decrease by 0.058 V
C. Increase by 0.41 V
D. Decrease by 0.41 V

Explanation

(A) Efficiency = `(/_\G^0)/(/_\H^0)= (-nE^0F)/(/_\H^0)` ,
`E^0= ("Efficiency"xx/_\H^0) /(-nF)` = `(70xx(-300xx10^(+3)))/(100xx(-1)xx96500)` = 2.176 V