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If e(Fe^(2+) //Fe)^@ =- 0. 44 1V. And E(...

If `e_(Fe^(2+) //Fe)^@ =- 0. 44 1V`. And `E_(Fe^(3+)//Fe^(2+))^(o) = 0. 771 V`. The standard emf of the reaction ` Fe +2 Fe^(3+) rarr 3Fe^(2+)` will be .

A

1.212 V

B

0.111 V

C

0.330 V

D

1.653 V

Text Solution

Verified by Experts

(A) `E_(cell)^0=E_(RPH_2O)^0` =0.44+1.23=1.67V
`:. /_\G^0` = `-nE^0F` =-2 `xx1.67xx96500J`
= -322.31 kJ `mol^-1`
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