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E^(@) for F(@)+2e hArr2F^(-) is 2.7 V ...

`E^(@)` for `F_(@)+2e hArr2F^(-)` is `2.7 V`
Thus, `E^(@)` for `F^(-) hArr(1)/(2)Fe +e` is :

A

1.35 V

B

-1.35V

C

-2.7 V

D

2.7V

Text Solution

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(A) Anode : 2`HCOO^- rarrH_2`+ 2`CO_2`+2e,
Cathode: `2H^+ +2e `rarr`H_2`
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