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5 litre solution of 0.4 M Ni(NO3 )2 is e...

5 litre solution of 0.4 M `Ni(NO_3 )_2` is electrolysed using Pt electrodes with 2.4125 ampere current for 10 hour

A

0.31 M

B

0.22 M

C

0.26 M

D

0.40 M

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To solve the problem step by step, we will follow the information provided in the video transcript while ensuring clarity in our calculations. ### Step 1: Identify the Given Information - Volume of the solution (V) = 5 liters - Molarity of the solution (M) = 0.4 M - Current (I) = 2.4125 A - Time (t) = 10 hours ...
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