The specific conductivity of 0.02 M KCl solution at `25^(@)C` is `2.768xx10^(-3) ohm^(-1) cm^(-1)`. The resistance of this solution at `25^(@)C` when measured with a particular cell was 250.2 ohm. The resistance of 0.01 M `CuSO_(4)` solution at `25^(@)C` measured with the same cell was 8331 ohm. Calculate the molar conductivity of the copper sulphate solution.

Explanation

Cell constant`=overset(Sp.cond. Of KCl)underset("Conductance of KCl")to=(2.768xx10^(-3)/(1//250.2))`
`=2.768xx10^(-3)xx250.2`
For 0.01 M `CuSO_4` solution
Sp. Conductivity=Cell constant `xx` conductane
`=2.768xx10^(-3)250.2xx1/(8331)`
Molar conductance=Sp. cond. `xx(1000)/C=(2.768xx10^(-3)xx250.2)/(8331)xx(1000)/(1/100)=8.312 ohm^(-1) cm^2 mol^(-1)`