In the electrolysis of `CuSO_4`, the reaction:`Cu^(2+)+2e^(-) rarr Cu`,takes place at:

Options

A. Anode
B. Cathode
C. In solution
D. None

Answer

To determine where the reaction `Cu^(2+) + 2e^(-) → Cu` takes place during the electrolysis of `CuSO4`, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Electrolysis**: Electrolysis is a chemical process that uses electricity to drive a non-spontaneous reaction. In this case, we are looking at the electrolysis of copper sulfate (CuSO4).

2. **Identifying the Components**: In the electrolysis of CuSO4, we have two electrodes: the cathode and the anode. The cathode is where reduction occurs (gain of electrons), and the anode is where oxidation occurs (loss of electrons).

3. **Analyzing the Given Reaction**: The reaction provided is `Cu^(2+) + 2e^(-) → Cu`. This indicates that copper ions (Cu^(2+)) are gaining two electrons to form solid copper (Cu).

4. **Determining the Electrode for the Reaction**: Since the reaction involves the gain of electrons, it is a reduction reaction. Reduction occurs at the cathode. Therefore, the reaction `Cu^(2+) + 2e^(-) → Cu` takes place at the cathode.

5. **Conclusion**: The correct answer to the question is that the reaction occurs at the cathode during the electrolysis of CuSO4.

### Final Answer:
The reaction `Cu^(2+) + 2e^(-) → Cu` takes place at the **cathode**.

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