The number of faraday required to generate 1 mole of Mg from `MgCl_2` is

Options

A. 1
B. 2
C. 3
D. 4

Answer

To determine the number of Faraday required to generate 1 mole of magnesium (Mg) from magnesium chloride (MgCl₂), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reaction**:
The dissociation of magnesium chloride in solution can be represented as:
\[ MgCl_2 \rightarrow Mg^{2+} + 2Cl^- \]
Here, magnesium exists in the +2 oxidation state.

2. **Reduction of Magnesium Ion**:
To obtain solid magnesium from magnesium ions, the following reduction reaction occurs:
\[ Mg^{2+} + 2e^- \rightarrow Mg \]
This shows that 1 mole of magnesium ions (Mg²⁺) requires 2 moles of electrons (2e⁻) to be reduced to 1 mole of magnesium (Mg).

3. **Relate Moles of Electrons to Faraday**:
According to Faraday's laws of electrolysis, 1 mole of electrons corresponds to 1 Faraday (approximately 96500 coulombs). Therefore, if 2 moles of electrons are needed, the number of Faraday required can be calculated as:
\[ \text{Number of Faraday} = \text{Moles of electrons} = 2 \text{ moles of electrons} = 2 \text{ Faraday} \]

4. **Conclusion**:
Thus, the number of Faraday required to generate 1 mole of magnesium from magnesium chloride (MgCl₂) is 2.

### Final Answer:
The number of Faraday required to generate 1 mole of Mg from MgCl₂ is **2**.

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