The best conductor of electricity is in 1M solution of

Options

A. `CH_3COOH`
B. `H_2SO_4`
C. `H_3PO_4`
D. Boric acid

Answer

To determine the best conductor of electricity in a 1M solution among the given options, we need to analyze the ionization properties of each compound. The conductivity of a solution largely depends on the concentration of ions present, which are responsible for carrying the electric current.

### Step-by-Step Solution:

1. **Identify the Options**: The options provided are:
- Acetic Acid
- H2SO4 (Sulfuric Acid)
- H3PO4 (Phosphoric Acid)
- Boric Acid

2. **Analyze Acetic Acid**:
- Acetic Acid (CH3COOH) is a weak acid.
- It does not ionize completely in solution.
- Therefore, it produces fewer ions, resulting in lower conductivity.

3. **Analyze H2SO4 (Sulfuric Acid)**:
- H2SO4 is a strong acid and is known for its complete ionization.
- In the first step, it dissociates into H+ and HSO4- ions.
- In the second step, HSO4- can further dissociate into H+ and SO4^2- ions.
- This results in a high concentration of ions, making it an excellent conductor of electricity.

4. **Analyze H3PO4 (Phosphoric Acid)**:
- H3PO4 is a weak acid and does not ionize completely.
- It produces fewer ions compared to strong acids, thus it is not a good conductor of electricity.

5. **Analyze Boric Acid**:
- Boric Acid (H3BO3) is also a weak acid.
- It does not release H+ ions on its own; it requires water to ionize.
- This limited ionization results in low conductivity.

6. **Conclusion**:
- Among the given options, H2SO4 (Sulfuric Acid) is the best conductor of electricity in a 1M solution due to its complete ionization and high concentration of ions.

### Final Answer:
The best conductor of electricity in a 1M solution is **H2SO4 (Sulfuric Acid)**.

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