The resistance of 0.5M solution of an el...

The resistance of `0.5M` solution of an electrolyte in a cell was found to be `50 Omega`. If the electrodes in the cell are `2.2 cm` apart and have an area of `4.4 cm^(2)` then the molar conductivity (in `S m^(2) mol^(-1))` of the solution is

0.2

0.02

0.002

None of these

Text Solution

Verified by Experts

The correct Answer is:

Topper's Solved these Questions

ELECTROCHEMISTRY
MOTION|Exercise EXERCISE -2 (LEVEL-2)|26 Videos
ELECTROCHEMISTRY
MOTION|Exercise EXERCISE-3|100 Videos
ELECTROCHEMISTRY
MOTION|Exercise EXERCISE -1|43 Videos
D-BLOCK ELEMENTS
MOTION|Exercise Exercise IV Level-II|9 Videos
GASEOUS STATE
MOTION|Exercise EXERCISE-4( LEVEL-II)|19 Videos

Similar Questions

Explore conceptually related problems

The resistance of 0.5 N solution of an electroolyte in a conductivity cell was found to be 45 ohms. If the electrodes in the cell are 2.2 cm apart and have an area of 3.8cm^(2) then the equivalent conductance (in Scm^(2)eq^(-1) ) of a solution is

The resistance of a (N)/(10)KCl aqueous solution is 2450Omega . If the electrodes in the cell are 4cm apart abd area having 7 cm^(2) each, the molar conductance of the solution will be

The resistance of 0.5 M solution of and electrolyte enclosed enclosed between two platinuim electrodes 1.56 cm apart and having an are of 2.0cm^(3) was found to be 30 cm. Calculate the molar conductivity of the electrolyte/.

The resistance of aN//10KCI solution is 245 Omega . Calculate the equivalent conductance of the solution if the electrodes in the cell are 4 cm apart and each haveing an area of 7.0 sq.cm .

(a). The resistance of a decinormal solution of an electrolyte in a conductivity cell was found to be 245 ohms. Calculate the equilvalet conductivity of the solution if the electrodes in the cell were 2 cm apart and each has an area of 3.5 sq. cm. (b). The conductivity of 0.001028M acetic acid is 4.95xx10^(-5)Scm^(-1) . Calculate its dissociation constant if ^^_(m)^(@) for acetic acid is 390.5Scm^(2_mol^(-1)

The resistance of an N//10 KCl solution is 245 ohms . Calculate the equivalent conducatnce of the solution id the electrodes in the cell are 4 cm apart and each having an area of 7.0 sq.cm.

MOTION-ELECTROCHEMISTRY-EXERCISE -2 (LEVEL-1)

For how long 2.5 ampere of current is passed to supply 5400C of charge...
Text Solution
|
1 faraday of electricity will liberate 1 gram atom of the metal from t...
Text Solution
|
A solution containing one mole per litre of each Cu(NO(3))(2), AgNO(3)...
Text Solution
|
A current of 2 ampere was passed through solutions of CuSO4 and AgNO3 ...
Text Solution
|
On passing 3 A of electricity for 50 min, 1.8 g of metal deposits. The...
Text Solution
|
The number of coulombs required to deposit 5.4g of Al when the electro...
Text Solution
|
The specific conductance of a solution is 0.3568 " ohm"^(-1) cm^(-1) w...
Text Solution
|
A conductance cell was filled with a 0.02 M KCl solution which has a s...
Text Solution
|
The variation of equivalent conductance verses concentration of a stro...
Text Solution
|
Which of the following solutions has the highest equivalent conductanc...
Text Solution
|
The resistance of 0.01N solution of an electrolyte AB at 328K is 100oh...
Text Solution
|
For an electrolyte solution of 0.05 mol L^(-1) , the conductivity has...
Text Solution
|
Twoelectrodes are fitted in conductance cell 1.5 cm apart while the ar...
Text Solution
|
The best conductor of electricity is in 1M solution of
Text Solution
|
The resistance of 0.5M solution of an electrolyte in a cell was found ...
Text Solution
|
Equivalent conductance of 0.1 M HA (weak acid) solution is 10 Scm^2 eq...
Text Solution
|
If x is specific resistance of the electrolyte solution and y is the m...
Text Solution
|
The dissociation constant of n-butyric acid is 1.6 xx 10^(-5) and the ...
Text Solution
|
The conductivity of a saturated solution of Ag(3)PO(4) is 9 xx 10^(-6)...
Text Solution
|
A saturated solution in AgA (K(sp)=3xx10^(-14)) and AgB (K(sp)=1xx10^(...
Text Solution
|