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The maximum tendency to form unipositive...

The maximum tendency to form unipositive ion is for the elment with the electronic configuration :

A

`1s^(2) , 2s^(2) , 2p^(6) , 3s^(2)`

B

`1s^(2) , 2s^(2) , 2p^(6) , 3s^(2) , 3p^(1)`

C

`1s^(2) , 2s^(2) , 2p^(6) , 3s^(2) , 3p^(2)`

D

`1s^(2) , 2s^(2)sp^(6) , 3s^(2) 3p^(3)`

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The correct Answer is:
To determine which element has the maximum tendency to form a unipositive ion (a cation with a +1 charge), we need to analyze the given electronic configurations. A unipositive ion is formed when an atom loses one electron. The stability of the resulting electronic configuration plays a crucial role in determining the tendency to form such an ion. ### Step-by-Step Solution: 1. **Understanding Unipositive Ions**: A unipositive ion is formed when an atom loses one electron. The stability of the resulting electron configuration is key to determining the tendency to form this ion. 2. **Analyzing Electronic Configurations**: - **Configuration 1**: 3s² - This configuration has a fully filled s-orbital. Removing one electron would lead to a less stable configuration (3s¹), making the tendency to form a unipositive ion very low. - **Configuration 2**: 3s² 3p¹ - Here, the last electron is in the 3p orbital. If one electron is removed (from 3p¹), the resulting configuration would be 3s², which is stable. Hence, this configuration has a higher tendency to form a unipositive ion. - **Configuration 3**: 3s² 3p² - Removing one electron from 3p² would lead to 3p¹. This configuration does not have a significant stability difference compared to the original, so the tendency to form a unipositive ion is moderate. - **Configuration 4**: 3s² 3p³ - This configuration has a half-filled p-orbital. Removing one electron would lead to 3p², which is less stable than the half-filled state, thus reducing the tendency to form a unipositive ion. 3. **Conclusion**: After analyzing all configurations, the configuration with the highest tendency to form a unipositive ion is **3s² 3p¹** (Option 2). This is because removing one electron leads to a stable, fully filled orbital configuration (3s²). ### Final Answer: The element with the electronic configuration **3s² 3p¹** has the maximum tendency to form a unipositive ion.
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MOTION-PERIODIC TABLE -Exercise - 1
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  3. The maximum tendency to form unipositive ion is for the elment with th...

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  4. The second ionisation potentials in electron volts of oxygen and fluor...

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  5. A sudden large jump between the values of second and third ionisation ...

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  6. The correct order of stability of Al^(+) , Al^(+2) , Al^(+3) is :

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  7. The ionization energy of sodium is 495 kJ mol^(-1). How much energy is...

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  8. Ionisation energy increases in the order :

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  9. Mg forms Mg(II) because of :

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  10. IE(1) and IE(2) of Mg are 178 and 348 kcal mol^(-1). The energy requir...

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  11. Highest ionisation potential in a period is shown by

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  12. In which case the energy released is minimum -

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  13. In the formation of a chloride ion, from an isolated gaseous chlorine ...

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  14. The correct order of electron affinity is:

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  15. The screening effect of d-electron is

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  16. The X-X bond length is 1.00A^(0) and C-C bond length is 1.54A^(@). If ...

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  17. Electronegativity scale of pauling is based upon -

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  18. The correct set of decreasing order of electronegativity is

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  19. Which of the following is affected by stable configuration of an atom ...

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  20. Correct order of electronegativity of N,P,C and Si on Pauling scale is...

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