In the following which configuration of element has maximum electronegativity.

Options

A. `1s^(2) , 2s^(2) , 2p^(5)`
B. `1s^(2) , 2s^(2) , 2p^(6)`
C. `1s^(2) , 2s^(2) , 2p^(4)`
D. `1s^(2) , 2s^(2) , 2p^(6) , 3s^(2) , 3p^(3)`

Answer

To determine which configuration of an element has the maximum electronegativity, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Electron Configurations**:
The configurations given in the question are:
- 2p5
- 2p6
- 2p4
- 3s2, 3p3

2. **Determine the Period and Group**:
- **2p5**: This configuration corresponds to Fluorine (F), which is in Period 2 and Group 17.
- **2p6**: This configuration corresponds to Neon (Ne), which is in Period 2 and Group 18.
- **2p4**: This configuration corresponds to Oxygen (O), which is in Period 2 and Group 16.
- **3s2, 3p3**: This configuration corresponds to Phosphorus (P), which is in Period 3 and Group 15.

3. **Analyze Electronegativity Trends**:
Electronegativity generally increases across a period (from left to right) and decreases down a group (from top to bottom). Therefore:
- **Fluorine (2p5)** has the highest electronegativity in Group 17.
- **Neon (2p6)** is a noble gas and does not have electronegativity.
- **Oxygen (2p4)** has lower electronegativity than Fluorine.
- **Phosphorus (3s2, 3p3)** has lower electronegativity than both Fluorine and Oxygen.

4. **Conclusion**:
Among the configurations analyzed, Fluorine (2p5) has the maximum electronegativity because it is the most electronegative element in the periodic table.

### Final Answer:
The configuration with maximum electronegativity is **2p5 (Fluorine)**.