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Bond distance C-F in (CF(4)) & Si-F in ...

Bond distance `C-F` in `(CF_(4))` & `Si-F` in `(SiF_(4))` are respective `1.33 Å` & `1.54 Å. C-SI` bond is `1.87 Å`. Calculate the colvalent radius of F atom ignoring the electronegativity differences.

A

`0.64` Å

B

`(1.33 + 1.54 + 1.8)/(3)` Å

C

`0.5` Å

D

`(1.54)/(2)` Å

Text Solution

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The correct Answer is:
C
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MOTION-PERIODIC TABLE -Exercise - 2 (Level-I)
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  6. Highest size will be of

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  9. Four elements P,Q,R & S have ground state electronic configuration as:...

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  10. False statement for periodic classification of element is

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  11. The correct order of second ionisation potential of C, N, O and F is:

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  12. The ionization energy will be maximum for the process.

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  13. Element in which maximum ionization energy of following electronic con...

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  18. In the following which configuration of element has maximum electroneg...

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  19. Bond distance C-F in (CF(4)) & Si-F in (SiF(4)) are respective 1.33 Å...

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