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If 3x+4y+z=5, where x,y,z in R, then min...

If `3x+4y+z=5,` where `x,y,z in R,` then minimum value of `26(x^2+y^2+z^2)` is

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Given that x ,y ,z are positive real such that x y z=32. If the minimum value of x^2+4x y+4y^2+2z^2 is equal m , then the value of m//16 is.

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