A paper is in the form of a rectangle `A B C D` in which `A B=20 c m` and `B C=14 c mdot` A semi-circular portion with BC as diameter is cut off. Find the area of a remaining part.

Explanation

Area of the remaining part of sheet = Area of `ABCD` - Area of a semi-circle


`=20 times 14-frac{1}{2} times frac{22}{7} times frac{14}{2} times frac{14}{2}`


`=280-77=203 cm^{2}`