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P Aa n dP B are tangents from P to the c...

`P Aa n dP B` are tangents from `P` to the circle with centre `Odot` At point `M ,` a tangent is drawn cutting `P A` at `K` and `P B` at `Ndot` Prove that `K N=A K+B Ndot`

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`KM=AK `( tangents on the circle from external point K)
`MN=BN` ( tangents on the circle from external point N)
As we know,
`KN=KM+MN`
`:.KN=AK+BN` ( because KM=AK and MN=BN)
Hence proved,
`KN=AK+BN`
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