The product of the 9 fractions `(1-1/2)(1-1/3)(1-1/4)...(1-1/10)=...`

When simplified the product (1 - 1/2) (1 - 1/3) (1 - 1/4) .........(1-1/n) gives :

If 1 added to the denominator of a fraction,the fraction becomes (1)/(2)* If 1 is added to the numerator of the fraction,the fraction becomes 1. The fraction is (1)/(3) b.(2)/(3) c.(3)/(4) d.(3)/(2)

Find the value of (1-1/(2^(2)))(1-1/(3^(2)))(1-1/(4^(2)))(1-1/(5^(2)))…….(1-1/(9^(2)))(1-1/(10^(2)))

I : The partial fractions of (2x+3)/((x+1)(x-3)) " are " 9/(4(x-3))-1/(4(x+1)) . II : The partial fractions of 2/((x+1)(x+3)) " are " 1/(x+1)-1/(x+3) .

The sum of 10 terms of the series 1+2(1.1)+3(1.1)^(2)+4(1.1)^(3)+…. is

The sum of 10 terms of the series 1+2(1.1)+3(1.1)^(2)+4(1.1)^(3)+…. is