A 2.0 V potentiometer is used to determine the internal resistance of `1.5 V` cell. The balance point of the cell in the circuit is `75 cm`. When a resistor of `10Omega` is connected across cel, the balance point sifts to `60 cm`. The internal resistance of the cell is

A 2.0V potentiometer is used to determine the internal resistance ofa I.SY cell. The balance point of the cell in the open circuit is obtained at 75cm. When· a resistor of 10Omega is connected across the cell, the balance point shifts to 60cm. The internal resistance of the cell is:

Figure 3.35 shows a 2.0 V potentiometer used for the determination of internal resistance of a 1.5 V cell. The balance point of the cell in open circuit is 76.3 cm. When a resistor of 9.5 Omega is used in the external circuit of the cell, the balance point shifts to 64.8 cm length of the potentiometer wire. Determine the internal resistance of the cell. :

Figure shows a 2.0 V potentiometer used for the determination of internal resistance of a 1.5 V cell. The balance point of the cell in open circuit is 76.3 cm. When a resistor of 9.5 Omega is used in the external circuit of the cell, the balance point shifts to 64.8 cm length of the potentiometer wire. Determine the internal resistance of the cell

Figure shows a 2.0 V potentiometer used for the determination of internal resistance of a 1.5 V cell. The balance point of the cell in open circuit is 76.8 cm. when a resistor of 9.5 Omega is used in the external circuit of the cell, the balance point shifts to 64.8 cm length of the potentiometer wire. Determine the internal resistance of the cell.

Figure shows a 2.0 V potentiometer used for the determination of internal resistance of a 1.5 V cell.The balance point of the cell in open circuit is 76.3 cm.When a resistor of 9.5 Omega is,used in the external circuit of the cell,the balance point shifts to 64.8 cm length of the potentiometer wire. Determine the internal resistance of the cell.

show a 2.0V potentiometer used for the determination of internal resistance of a 1.5V cell. The balance point of the cell in open circuit is 76.3 cm. When a resistor of 9.5Omega is used in the external circuit of the cell, the balance point shifts to 64.8 cm length of the potentiometer wire. Determine the internal resistance of the cell.