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[(4)/(x)+3y=8],[(6)/(x)-4y=-5]...

[(4)/(x)+3y=8],[(6)/(x)-4y=-5]

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Solve the following system of equations: (4)/(x)+3y=8,quad (6)/(x)-4y=-5

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(1)/(3)x+(1)/(4)y=4,(5)/(6)x-(1)/(8)y=4

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4x-3y=8, 6x-y=29/3

(x-4)(x-3)=(x-6)(x-5) (y-9)(y-3)= (y-4)(y-3)

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The following steps are involved in finding the value of x.y, if (3x + 4y)/(2x + 5y) = (4)/(3). Arrange them in sequential order from the first to the last. (A) 9x + 12 y = 8x + 20y (B) Given, (3x + 4y)/(2x + 5y) = (4)/(3) (C) (x)/(y) = 8 rArr x:y = 8:1 (D) (3x + 4y)3 = (2x + 5y)4 (E) x = 8y

x+(6)/(y)=6,3x-(8)/(y)=5 then y=………