Find the values(s) of `k` for which the system of equations `k x-y=2` `6x-2y=3` has (i) a unique solution (ii) no solution. Is there a value of `k` for which the system has infinitely many solutions?

Explanation

Given

`kx−y−2=0
`
and `6x−2y−3=0
`

We know that for `a_1​x+b_1​y+c_1​=0,a_2​x+b_2​y+c_2​=0`

`(a_1)/(​a_2)​​=(b_1)/(​b_2)​​!=(c_1)/(​c_2)​`​ for no solution

`a_1​=k,b_1=−1,c_1​=−2`

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