If `aN = {ax:x in N} and bNnncN=dN,`where`b,cin N` are relatively prime, then show that `d=bc`.

if a N= {a x:x in N} and b N cap c N = dN , where b,c in N are relatively prime , then

if a N= {a x:x iin N} and b N cap c N , where b,c in N are relatively prime , then

If aN = {ax : x in N} " and " bN cap cN = dN " where " b,c in N are relatively prime then

If aN = {ax|x in N} and bN nn cN = dN , where b,c epsilon N , then

If aN = {ax|x in N} and bN nn cN = dN , where b,c epsilon N , then

If aN = {an : n in N} and bn nn cN = dN where a, b, c, d in N and b, c are relatively prime then

Let N be the set of natural numbers and for a in N , aN denotes the set {ax : x in N} . If bNnncN=dN , where b, c, d are natural numbers greater than 1 and the greatest common divisor (GCD) of b and c is 1, then d equals

Let N be the set of natural numbers and for a in N , aN denotes the set {ax : x in N} . If bNnncN=dN , where b, c, d are natural numbers greater than 1 and the greatest common divisor (GCD) of b and c is 1, then d equals

Let N be the of natural number and for a in N , aN denotes the set {ax:x in N} . If bN nn cN=dN , where b, c, d are natural numbers greater than 1 and the greatest common divisor of b and c is 1 then d equals