" ve : "(cos8A cos5A-cos12A cos9A)/(sin8A cos5A+cos12A sin9A)=tan4A

Prove that: (cos8A cos5A-cos12A cos9A)/(sin8A cos5A+cos12A sin9A)=tan4A

showthat::(cos8A cos5A-cos12A cos9A)/(sin8A cos5A+cos12A sin9A)=tan4A

Show that (cos8Acos5A-cos12Acos9A)/(sin8Acos5A+cos12Asin9A)=tan4A

(cos 8 A cos 5A-cos 12 A cos 9A)/(sin 8 A cos 5 A +cos 12Asin 9A)=

Prove that: (cos5A.cos8A-cos12A.cos9A)/(sin8A.cos5A+cos12A. sin9A)=tan4A

Prove that: ("cos"8Acos5A-cos12 Acos9A)/("sin"8Acos5A+cos12 Asin9A)=tan4A

Show that (cos 8Acos 5A-cos12Acos 9A)/(sin 8Acos 5A+cos 12Asin 9A)=tan 4A

Show that (cos 8 A cos 5A - cos 12 A cos 9A )/( sin 8 A cos 5A + cos 12 A sin 9A ) = tan 4A

(sinA + sin3A) / (cosA + cos3A) = tanalpha, (cosA-cos2A) / (sinA + sin2A) = tanbeta, (sinA + sin3A + sin5A + sin7A) / (cosA + cos3A + cos5A + cos7A) = tan gamma , (cosA-cos5A-cos9A + cos13A) / (sinA-sin5A + sin9A-sin13A) = tandelta, then (a) alpha = 4beta (b) gamma = 2alpha (c) gamma = delta (d) none

(sin7A-sin5A)/(cos7A+cos5A)=tan A