`(44)/(x+y)+(30)/(x-y)=10` `(55)/(x+y)+(40)/(x-y)=13`

Explanation

To solve the system of equations given by:

\[ \frac{44}{x+y} + \frac{30}{x-y} = 10 \quad \text{(1)} \]
\[ \frac{55}{x+y} + \frac{40}{x-y} = 13 \quad \text{(2)} \]
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