The area of the triangle formed by the lines `2x+3y=12 ,x-y-1=0` and `x=0` (as shown in Figure), is 7sq. units (b) 7.5 sq. units (c) 6.5 sq. units (d) 6 sq. units

Explanation

To find the area of the triangle formed by the lines \(2x + 3y = 12\), \(x - y - 1 = 0\), and \(x = 0\), we will follow these steps:

### Step 1: Find the intersection points of the lines
We need to find the points where the lines intersect. The three lines are:
1. \(2x + 3y = 12\) (Line 1)
2. \(x - y - 1 = 0\) (Line 2)
3. \(x = 0\) (Line 3)

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