Home
Class 12
CHEMISTRY
ointvec B*dvec l=mu(0)l...

ointvec B*dvec l=mu_(0)l

Promotional Banner

Similar Questions

Explore conceptually related problems

If vecB_(1),vecB_(2) and vecB_(3) are the magnetic field due to l_(1),l_(2) and l_(3) , then in Ampere's circuital law ointvecB.vec(dl)=mu_(0)l, vecB is

The maxwells four equations are written as ( i ) ointvecE.vec(dS)=(q_(0))/(epsilon_(0)) ( ii ) ointvecB.vec(dS)=0 ( iii ) ointvecE.vec(dl)=(d)/(dt)ointvecB.vec(dS) ( iv ) ointvecB.vec(dl)=mu_(0)epsilon_(0)(d)/(dt)ointvecE.vec(dS) The equations which have sources of vecE and vecB are

Statement I: no electric current will be present within a region having uniform and constant magetic field. Statement II: Within a region of unifrom and cinstant magnetic field vec(B) , the path integral of magnetic field oint vec(B).dvec(l) along any closed path is zero. Hence, from Ampere cirauital law oint vec(B).dvec(l) = mu_(0)I (where the given terms ahve usual meaning), no current can be present within a region having uniform and constant magnetic field .

Statement I: no electric current will be present within a region having uniform and constant magetic field. Statement II: Within a region of unifrom and cinstant magnetic field vec(B) , the path integral of magnetic field oint vec(B).dvec(l) along any closed path is zero. Hence, from Ampere cirauital law oint vec(B).dvec(l) = mu_(0)I (where the given terms ahve usual meaning), no current can be present within a region having uniform and constant magnetic field .