A piggy bank contains hundred 50 paise coins, fifty Rs. 1 coins, twenty Rs. 2 coins and ten Rs. 5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, find the probability that the coin which fell will be a 50 paise win will be of value more than Rs. 1 will be of value less than Rs. 5 will be a Rs. 1 or Rs. 2 coin.

Explanation

Total no. of coins in the piggy is 180

Solution(i):

No. of 50 {p} coins in piggy is 100

Let mathrm{E} be the event of drawing a coin from piggy

We know that, Probability P (E)`=frac{ { (No.of favorable outcomes) }}{ { (Total no. of possible outcomes) }}=frac{100}{180}=frac{5}{9}`

Therefore,Probability that a 50p coin wins `=frac{5}{9}`

Solution(ii):

No. of coins with value >=Rs. 1 in piggy is 30
...