=xyquad " 9."x^(2)+y^(2)=log(xy)

Similar Questions

Explore conceptually related problems

derivative of x^(2)+y^(2)=log(xy)

Find (dy)/(dx) , when: x^(2)+y^(2)=log(xy)

The solution of xy.log((x)/(y))dx+{y^(2)-x^(2)log((x)/(y))}dy =

If x^(2)+y^(2)=14xy and 2log(k(x+y))=(log x+log y) ,then the value of k is

Simplify the following : 3xy^(2) - 5x^(2)y + 7xy - 9xy^(2) - 4xy + 6x^(2)y

12xy (9x ^ (2) -16y ^ (2)) -: 4xy (3x + 4y)

If log((x-y)/(5))=(1)/(2)log x+(1)/(2)log y, show that x^(2)+y^(2)=27xy

If u=log((x^(2) + y^(2))/(xy)) , then

Add : x^(3) - x^(2)y + 5xy^(2) + y^(3) , -x^(3) - 9xy^(2) + y^(3), 3x^(2)y + 9xy^(2)

If y =a cos (log x) + b sin (log x) then x ^(2) y _(2) + xy _(1)+y=