x^(p)y^(q)=(x+y)^(p+q)

Form the differntial equation which is satisfied by x ^p^y^q=lambda(x+y)^(p+q) , where lambda is arbitrary constant.

(2) If a=x^(q+r)*y^(p) , b=x^(r+p)*y^(q) , c=x^(p+q)y^(r) , show that a^(q-r)b^(r-p)c^(p-q)=1

Write down the order of the differential equation which is satisfied by all functions of the type x^p y^q=lambda(x+y)^(p+q) , where lambda is an arbitrary constant.

Solve for x and y:(q)/(p)x+(p)/(q)y=p^(2)+q^(2);x+y=2pq

If (log x)/(q-r)=(log y)/(r-p)=(log z)/(p-q) prove that x^(q+r)*y^(r+p)*z^(p+q)=x^(p)*y^(q).z^(r)

Solve the following system of equations.(x)/(p)+(y)/(q)=1p(x-p)-q(y+q)=2p^(2)+q^(2)

Solve the following system of equations.(x)/(p)+(y)/(q)=1p(x-p)-q(y+q)=2p^(2)+q^(2)

(((1)/(x)+y)^((a+b))((1)/(y)-x)^(-(p+q)))/(((1)/(x)-y)^(-(p+q))(x+(1)/(y))^((a+b)))=