If x+y=0,x-y=0 are tangents to a parabola whose focus is (1,2) Then the length of the latusrectum of the parabola is equal

L_(1):x+y=0 and L_(2)*x-y=0 are tangent to a parabola whose focus is S(1,2). If the length of latus-rectum of the parabola can be expressed as (m)/(sqrt(n)) (where m and n are coprime then find the value of (m+n)

Find the vertex, focus, directrix and length of the latus rectum of the parabola y^2 - 4y-2x-8=0

Find the equation of parabola whose focus is (0,1) and the directrix is x+2=0. Also find the vertex of the parabola.

Find the equation of parabola whose focus is (0,1) and the directrix is x+2=0. Also find the vertex of the parabola.

Consider the parabola whose focus is at (0,0) and tangent at vertex is x-y+1=0 The length of latus rectum is

Two tangents on a parabola are x-y=0 and x+y=0. S(2,3) is the focus of the parabola. The length of latus rectum of the parabola is

Find the equation of the parabola whose focus is (1,1) and tangent at the vertex is x+y=1

Statement-1: Length of the common chord of the parabola y^(2)=8x and the circle x^(2)+y^(2)=9 is less than the length of the latusrectum of the parabola. Statement-2: If vertex of a parabola lies at the point (a. 0) and the directrix is x + a = 0, then the focus of the parabola is at the point (2a, 0).