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Ten years ago, a father was twelve times...

Ten years ago, a father was twelve times as old as his son and ten years hence, he will be twice as old as his son will be then. Find their present ages.

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To solve the problem, we will define the present ages of the father and son, set up equations based on the information given, and then solve those equations step by step. ### Step 1: Define Variables Let: - \( x \) = Father's present age - \( y \) = Son's present age ### Step 2: Set Up the First Equation ...
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RD SHARMA-PAIR OF LINEAR EQUATIONS IN TWO VARIABLES-All Questions
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  14. Seven times a two-digit number is equal to four times the number ob...

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