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Ten years ago, a father was twelve times...

Ten years ago, a father was twelve times as old as his son and ten years hence, he will be twice as old as his son will be then. Find their present ages.

Text Solution

AI Generated Solution

To solve the problem, we will define the present ages of the father and son, set up equations based on the information given, and then solve those equations step by step. ### Step 1: Define Variables Let: - \( x \) = Father's present age - \( y \) = Son's present age ### Step 2: Set Up the First Equation ...
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Knowledge Check

  • Six years ago a man was three times as old as his son. In 6 years, he will be twice as old as his son Find their present ages.

    A
    30, 15
    B
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    A
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    B
    Father 55 and son 33
    C
    Father 66 and son 44
    D
    None of these
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    A
    27 years 3 years
    B
    30 years 3 years
    C
    33 years ,3 years
    D
    25 years 5 years
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