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A number is selected at random from the numbrs 3,5,5,7,7,7, 9,9,9,9. The probability that the selected number is their average is `1/(10)` (b) `3/(10)` (c) `7/(10)` (d) `9/(10)`

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Average of numbers
`=(3+5+5+7+7+7+9+9+9+9)/(10)=70/10=7`
Total number of numbers which are average of these numbers are `3`
We know that PROBABILITY=number of favourable event/ total number of events
...
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